I believe the answer is B. Optimization because it means to make work more efficient but I might be wrong. Checking definitions, this one seems more logical.
Answer:
The code will give an error that is "At least one public class is required in main file".
Explanation:
In the given code if we do not use the public access modifier to the class. It will give an error so, the correct code to this question as follows:
Program:
import java.util.HashSet; //import package
public class A //define class as public.
{
public static void main(String[ ] args) //define main method.
{
HashSet set = new HashSet(); //creating hashset object.
set.add("A"); //add alphabet in hashset
set.add("B"); //add alphabet in hashset
set.add("C"); //add alphabet in hashset
System.out.print("Size of HashSet is :"set.size()); //print the size of hashset.
}
}
Output:
Size of HashSet is : 3
Explanation of the program:
- In the above program, we define a public class that is "A" and inside the class, we define the main method.
- Inside the main method, we create a HashSet class object that is "set".
- To add elements in HashSet we use add() function that adds elements and in the last, we use the size() function that prints the size HashSet.
