Question

Divide (3+2i)/(-4+5i). express answer in standard form

Answer 1

$\dfrac{3+2i}{-4+5i}=\dfrac{(3+2i)(-4-5i)}{(-4+5i)(-4-5i)}=\dfrac{-12-15i-8i-10i^2}{(-4)^2-(5i)^2}\\\\=\dfrac{-12-23i+10}{16+25}=\dfrac{-2-23i}{41}=-\dfrac{2}{41}-\dfrac{23}{41}i$