3 years ago

Divide (3+2i)/(-4+5i). express answer in standard form

1 answer:

8 0

$\dfrac{3+2i}{-4+5i}=\dfrac{(3+2i)(-4-5i)}{(-4+5i)(-4-5i)}=\dfrac{-12-15i-8i-10i^2}{(-4)^2-(5i)^2}\\\\=\dfrac{-12-23i+10}{16+25}=\dfrac{-2-23i}{41}=-\dfrac{2}{41}-\dfrac{23}{41}i$

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Answer:

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Step-by-step explanation:

Ohm's first law:

By Ohm's first law, the voltage is the multiplication of the current by the resistance, that is:

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The voltage is measured in Volts, the current in amps and the resistance in ohms.

In this question:

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