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Greeley [361]
3 years ago
12

How do I solve this?

Mathematics
2 answers:
iren2701 [21]3 years ago
8 0
First you collect the like term then variable one side coefficient one side and constant
Andre45 [30]3 years ago
8 0
It looks like you tried to distribute the 8, which you cant
what you can distribute is the negative sign
so fyi, distribution property
a(b+c) = ab+ac

(4w^2+4w +8) - (2w^2+3w -6)
now, this expression is equivalent to the one below, notice the -1
(4w^2+4w +8) +(-1) (2w^2+3w -6)

we distribute the -1
(4w^2+4w +8) - 2w^2 -3w +6

now, looking at the parenthesis on the left, since you cant add them together because they have different terms, we dont need the parenthesis

4w^2+4w +8 - 2w^2 -3w +6

Since addition is commutative, we can put like terms next to each other
parenthesis used to show like term groups
(4w^2- 2w^2) +(4w -3w) +(6 +8)

now, since the terms within the parenthesis are like terms, you can add/subtract them together
2w^2 + w +14

any questions



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Answer:

Step-by-step explanation:

Given the simultaneous equation 2p - 3q = 4 and 3p + 2q = 9, to get the value of p and q we will use elimination method.

2p - 3q = 4 ...................... 1 * 3

3p + 2q = 9 ..................... 2 * 2

Multiplying equation 1 by 3 and 3 by 2:

6p - 9q = 12

6p + 4q = 18

Subtracting both equation

-9q-4q = 12-18

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q = -6/-13

q = 6/13

Substituting q = 6/13 into equation 2

2p - 3(6/13) = 4

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2p = 4+18/13

2p = (52+18)/13

2p = 70/13

p = 70/26

p = 35/13

<em>Hence p = 35/13 and q = 6/13</em>

<em></em>

<em>b) </em>If if 223ₓ = 87 find x

Using the number base system and converting 223ₓ  to base 2 will give us;

223ₓ = 2*x² + 2*x¹ + 3*x⁰

223ₓ  = 2x²+2x+3

​

Substituting back into the equation, 2x²+2x+3 = 87

2x²+2x+3-87 = 0

2x²+2x-84 = 0

x²+x-42 = 0

On factorizing:

(x²+6x)-(7x-42) = 0

x(x+6)-7(x+6) = 0

(x+6)(x-7) = 0

x+6 = 0 and x-7 = 0

x = -6 and 7

<em>Hence the value of x is 7 (neglecting the negative value)</em>

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6x/-4 = - 3...multiply by -4
6x = -3 * -4
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