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timurjin [86]
3 years ago
14

Which number produces a rational number when added to 0.3?

Mathematics
1 answer:
Afina-wow [57]3 years ago
6 0

Basically you need to find the answer choice that is rational. That way the sum will also be rational.

√7 is irrational as well as π and 0.5050050005...

2/4 is the only rational option.

answer: D

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Ira Lisetskai [31]

B should be your answer. 125-360= -235

7 0
3 years ago
8. A box is filled with candies in different colors. We have 40 white candies, 24 green ones, 12
Darya [45]

Answer:

P(Green\ or\ Red) = 0.30

Step-by-step explanation:

Given

White = 40

Green = 24

Red = 12

Yellow = 24

Blue = 20

Required

P(Green\ or\ Red)

The total numbe of candy is:

Total = 40 + 24 + 12 + 24 + 20

Total = 120

This probability is calculated as:

P(Green\ or\ Red) = P(Green) + P(Red)

For each, we have:

P(Green\ or\ Red) = \frac{Green}{Total} + \frac{Red}{Total}

Take LCM

P(Green\ or\ Red) = \frac{Green+Red}{Total}

P(Green\ or\ Red) = \frac{24+12}{120}

P(Green\ or\ Red) = \frac{36}{120}

P(Green\ or\ Red) = 0.30

8 0
3 years ago
Mach the Zodiac to the Months (In order of Zodiac) (NO HELP FROM FRIENDS OR INTERNET)
Sergio [31]

Answer:

Virgo:september-october,

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
How do I get the area in this
Nostrana [21]
You have to do 4x4 and you will get 16in2 but out the 2 in the corner of inches that your area
8 0
3 years ago
If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95​% confident that the d
katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}

n = 118.6

Rounding up

We need a sample size of least 119

6 0
3 years ago
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