There it is i found it :)
This should be easy because we just have to use substitution method. Substitute the value of x from the second equation into the x of the first equation.
-4(2y) + 11y = 15
-8y + 11y = 15
3y = 15 ; y = 5
Substitute this value of y to either the first or second equation.
x = 2(5) = 10
The ordered pair is therefore (10,5).
Answer:
(−7)(−6)(−5) so the zeros are 5, 6, &7
Step-by-step explanation:
That makes no sense. Can you rephrase the question?
Answer: in standerd form you need to solve 1 + 3 then 1 - 2
Step-by-step explanation: