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polet [3.4K]
2 years ago
8

(-3,-3)

Mathematics
1 answer:
timofeeve [1]2 years ago
8 0

Answer: Option (4)

Step-by-step explanation:

The y-intercept of the line is (0, -1). This eliminates everything except for option (4).

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30 I am pretty sure

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What is the least common denominator for the fractions 56and38?
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The least common factor is 18

Step-by-step explanation:

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PLEASE HELP ME WITH THIS THANKS
kotykmax [81]

Answer:

SA = 1244.64 square centimeters

Step-by-step explanation:

From the attached figure

The formula of the surface area of the prism is SA = 2B + PH, where

  • B is the area of its base
  • P is the perimeter of its base
  • H is the distance between its bases

The base of the prism is a regular hexagon with side 8 cm

If you join each vertex of the hexagon with its center you will form 6 congruent triangles with base 8 cm and height 6.93 cm

The area of the hexagon = 6 × area of a triangle

∵ The base of the triangle = 8 cm

∵ Its height = 6.93 cm

- The formula of the area of a triangle is A = \frac{1}{2} × base × height

∴ Area of the triangle = \frac{1}{2} × 8 × 6.93 = 27.72 cm²

- Lets find the area of the hexagon

∴ The area of the hexagon = 6 × 27 .72 = 166.32 cm²

∴ B = 166.32 cm²

The formula of the perimeter of the regular hexagon is P = 6 × s, where s is the length of its side

∵ The side of the hexagon is 8 cm

∴ P = 6 × 8

∴ P = 48 cm

∵ The distance between the two bases is 19 cm

∴ H = 19 cm

Substitute the values of B, P and H in the formula of the surface area above

∵ SA = 2(166.32) + (48)(19)

∴ SA = 332.64 + 912

∴ SA = 1244.64 square centimeters

7 0
3 years ago
Which of these relations on {0, 1, 2, 3} are equivalence relations? Determine the properties of an equivalence re- lation that t
slava [35]

Answer:

The relations that are equivalence relations are a) and c)

Step-by-step explanation:

A relation on a set A is called an equivalence relation if it is reflexive, symmetric, and transitive

We are going to analyze each one.

a){ (0,0), (1,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

b){ (0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3) }

Is not an equivalence relation. Not reflexive: (1,1) is missing, not transitive: (0,2) and (2,3) are in the relation, but not (0,3)

c){ (0,0), (1,1), (1,2), (2,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

d){ (0,0), (1,1), (1,3), (2,2), (2,3), (3,1), (3,2) (3,3) }

Is not an equivalence relation. Not transitive: (1,3) and (3,2) are in the relation, but not (1,2)

e){ (0,0), (0,1) (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3) }

Is not an equivalence relation. Not symmetric: (1,2) is present, but not (2,1)Not transitive: (2,0) and (0,1) are in the relation, but not (2,1)

5 0
3 years ago
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