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2 years ago

What does it mean to divide figures into known shapes

Mathematics

1 answer:

Ede4ka [16]2 years ago

6 0

I think it means to split a shape into common shapes. I.e. splitting a house shape into a triangle and a square

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como calcular la cantidad de horas por proyecto si un contratista tiene 5,000 horas-hombres y el costo es de $10 y $12 por proye

Tju [1.3M]

Answer:

Each project has 2.500 man-hours

Step-by-step explanation:

Available man hours: 5000

For two projects Costs $

X: project A 10

Y: project B 12

Approach:

X + Y = 5000 => X = 5000 - Y

10 * X + 12 * Y = 55000

replacing:

10 * (5000 - Y) + 12 * Y = 55000

50000 - 10 * Y + 12 * Y = 55000

2 * Y = 55000 - 50000

Y = 5000/2

Y = 2500

For X:

X = 5000 - 2500

X = 2500

The number of hours available for each project are:

Projects Man hours

X: project A 2500

Y: project B 2500

6 0

2 years ago

The average mass of a giraffe is approximately 1x 10^8 kilograms. The average mass of a blue whale is approximately 2x 10^6 kilo

Basile [38]

Answer:

Giraffe = 1,000 kg

Whale = 2,000,000 kg

Step-by-step explanation:

Whale has 2,000 times the mass.

Can I please get Branliest and rate, like Thank you!

6 0

2 years ago

2(3w-5y) expanded <br>please

Snezhnost [94]

<h2><u>DISTRIBUTIVE PROPERTY</u></h2>

The distributive property indicates that multiplying a number by the sum of two addends is equal to multiplying each addend individually by the number and then adding the products together.

In general terms:

‎ ‏‏‎

<u>In this exercise</u>:

Let's apply the distributive property:

$\mathsf{2(3w - 5y)}$

$= \mathsf{2(3w) - 2(5y)}$

$= \boxed{\mathsf{6w - 10y}}$

‎ ‏‏‎

<h3><u>Answer</u>: 6w - 10y</h3>

‎ ‏‏‎

7 0

2 years ago

Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

7 0

2 years ago

- Write a system of equations in which one equation could be multiplied by-2 and the

iris [78.8K]

2x+5y=9

3x+7y=13

6x+15y=27

-6x-14y=-26

y=1

x=2

6 0

2 years ago