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Ivenika [448]
3 years ago
9

Sjdjwkfmwkfkekfmkdekjejwje

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
4 0

Answer:

I think yes but it could be no. Sorry if I am wrong but it should be yes.

zloy xaker [14]3 years ago
3 0
I Believe it is yes because no just doesn’t make sense
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155+137+25=317°
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Math Help!!
emmasim [6.3K]
Slope denoted as m can be calculated from 2 diff. points using the formula:
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12 = -11/25(0) + b
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7 0
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Find the exact value of x.
frozen [14]

Answer:

9*√3

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The exact value of Sin60 = √3/2

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3 years ago
Which of the following are true statements.
Mariulka [41]

Answer:

Second statement is true.

The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

Step-by-step explanation:

for first part of statement

The lengths 7, 40 and 41 can not be sides of a right triangle.

If the square of long side is equal to the sum of square of other two sides

then the given length can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

c^{2} =a^{2} +b^{2}----------(1)

Let c=41 and a = 7 and b=40

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41^{2} =7^{2} +40^{2}

1681=49+1600

1681=1649

Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.

for second part of statement.

The lengths 12, 16, and 20 can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

Let c=20 and a = 12 and b=16

20^{2} =12^{2} +16^{2}

400=144+256

400=400

Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.

Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

8 0
3 years ago
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