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kap26 [50]
3 years ago
7

There are several disadvantages for asexual reproduction, what would be an advantage

Biology
1 answer:
Leni [432]3 years ago
7 0

there is no need to find a mate

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Which of the following statements is TRUE, regarding your DNA and the DNA of a banana? Both are made up of the same amino acids
Inga [223]

The correct answer is option D

Both are made up of the same nucleotide, but in a different sequence

DNA is made up of same set of nucleotide only the sequence is different which generates different set of amino acids forming the proteins of different types.Proteins are the building blocks of DNA which are responsible for different characteristics of an individual.

8 0
3 years ago
A geneticist crossed pure breeding black mice with pure breeding brown mice. All the 992 mice in the F1 generation had black coa
uysha [10]

Answer:

C. An approximately three-to-one ratio of black to brown coated mice in F2 is accounted for by the black allele being dominant over the brown allele

Explanation:

Assuming the black genotype is BB and the brown genotype is bb.

At F1:

                 BB   x   bb = All Bb (black)

At F2:

                  Bb   x   Bb = BB (black), 2Bb (Black), bb (brown)

Th ratio of black to brown is 3:1

961 black : 317 brown is approximately 3:1.

Hence, the correct option is C.

<em>An approximately three-to-one ratio of black to brown coated mice in F2 is accounted for by the black allele being dominant over the brown allele</em>

4 0
3 years ago
Which pair of atoms will form an ionic bond?
devlian [24]
B. sodium and chloride because an ionic bond only form between oppositely charged particles.
7 0
3 years ago
Read 2 more answers
Write a title for each step of primary<br><br> succession
vladimir2022 [97]

Answer:

<em>The labels <u>I-VII</u> represent the different stages of primary succession. I-bare rocks, II-pioneers (mosses, lichen, algae, fungi), III-annual herbaceous plants, IV-perennial herbaceous plants and grasses, V-shrubs, VI-shade intolerant trees, VII-shade tolerant trees.</em>

4 0
2 years ago
Proteus vulgaris has a doubling time of roughly 28 minutes. If an initial population of 500 cells is allowed to grow for 6 hours
romanna [79]

<u>Answer:</u> The final population of Proteus vulgaris after 6 hours is 3.71\times 10^{6}cells

<u>Explanation:</u>

We are given:

Proteus vulgaris divides and doubles every 28 minutes

Total time given = 6 hours = 360 min      (Conversion factor: 1 hr = 60 min)

Number of times Proteus vulgaris doubles in 6 hours = \frac{360min}{28min}=12.857times

Calculating the number of bacteria after 6 hours under ideal conditions:

We are given:

Initial population = 500 cells

Number of times it doubles = 12.857 times

Final Proteus vulgaris population = 500\times 2^{12.857}=3709476.8=3.71\times 10^{6}cells

Hence, the final population of Proteus vulgaris after 6 hours is 3.71\times 10^{6}cells

8 0
3 years ago
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