Area of the electronic board is 9000 cm2
Step-by-step explanation:
Write ratios to represent the unknown actual length and width of the display to the scale length and width of the display.
The Electronic board always seems like a rectangular shape
Length= scale÷Actual = 5/36 = 5×36 = 180cm

Width=scale÷Actual = 1/50 = 1×50 = 50cm

Area of Rectangle = legnth × width
= 180cm × 50cm = 9000 cm2

Area of the electronic board is 9000 cm2
It is 10 times as much as .008
Do you see the pattern?
Answer:
40.24922.........
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
Your welcome back to the inputs is
X-intercept: y = 0
y-intercept: x = 0
3x + 4y = 0
x-intercept: subtitute y = 0
3x + 4 · 0 = 0
3x = 0
x = 0 → (0; 0)
y-intercept: subtitute x = 0
3 · 0 + 4y = 0
4y = 0
y = 0 → (0; 0)