Answer:
The capacity of the container is 2546.78 cm³.
Step-by-step explanation:
The volume of the frustum of a cone is:
![\text{Volume}=\frac{\pi h}{3}\cdot[R^{2}+Rr+r^{2}]](https://tex.z-dn.net/?f=%5Ctext%7BVolume%7D%3D%5Cfrac%7B%5Cpi%20h%7D%7B3%7D%5Ccdot%5BR%5E%7B2%7D%2BRr%2Br%5E%7B2%7D%5D)
The information provided is:
r = 16/2 = 8 cm
R = 24/2 = 12 cm
h = 8 cm
Compute the capacity of the container as follows:
![\text{Volume}=\frac{\pi h}{3}\cdot[R^{2}+Rr+r^{2}]](https://tex.z-dn.net/?f=%5Ctext%7BVolume%7D%3D%5Cfrac%7B%5Cpi%20h%7D%7B3%7D%5Ccdot%5BR%5E%7B2%7D%2BRr%2Br%5E%7B2%7D%5D)
![=\frac{\pi\cdot8}{3}\cdot[(12)^{2}+(12\cdot 8)+(8)^{2}]\\\\=\frac{8\pi}{3}\times [144+96+64]\\\\=\frac{8\pi}{3}\times304\\\\=2546.784445\\\\\approx 2546.78](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Cpi%5Ccdot8%7D%7B3%7D%5Ccdot%5B%2812%29%5E%7B2%7D%2B%2812%5Ccdot%208%29%2B%288%29%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5Cfrac%7B8%5Cpi%7D%7B3%7D%5Ctimes%20%5B144%2B96%2B64%5D%5C%5C%5C%5C%3D%5Cfrac%7B8%5Cpi%7D%7B3%7D%5Ctimes304%5C%5C%5C%5C%3D2546.784445%5C%5C%5C%5C%5Capprox%202546.78)
Thus, the capacity of the container is 2546.78 cm³.
Answer:
Step-by-step explanation:
9.65+0.4=10.05
16.058-1.2=14.858
Answer:1/5, 5/8, 2/3
Step-by-step explanation:
Using 1/2 as a benchmark, 1/5 is the only one less than 1/2. That is the least. You can turn 2/3 and 5/8 into fractions with common denominators. 2/3=16/24 and 5/8= 15/24. 5/8 is less than 2/3, therefore resulting in the answer.
Step-by-step explanation:
The answer is letter B. Negative and Negative is Positive.
Answer:
1/64
Step-by-step explanation:
There are 8 equal sections
P(1) = 1/8 since there is one section with a 1 out of the 8 sections
Then we spin again
P(2) = 1/8 since there is one section with a 2 out of the 8 sections
P(1, then 2) = P(1) * P(2) since they are independent events
= 1/8 * 1/8
= 1/64