<h2>Answer:</h2><h3>=60</h3><h2>Step-by-step explanation:</h2><h3>=Solution:</h3><h3> (8+2) × (8-2)</h3><h3> =10×6</h3><h3> =60#</h3>
Answer:
24 bowls
Step-by-step explanation:
Its 24 bowls because 1/4 fits into one bowl. 4 bags of popcorn with fit in 4 bowls. So then 6 times 4 equals 24.
Answer:
The table a not represent a proportional relationship between the two quantities
The table b represent a proportional relationship between the two quantities
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form
or 
<u><em>Verify each table</em></u>
<em>Table a</em>
Let
A ----> the independent variable or input value
B ----> the dependent variable or output value
the value of k will be

For A=35, B=92 ---> 
For A=23, B=80 ---> 
the values of k are different
therefore
There is no proportional relationship between the two quantities
<em>Table b</em>
Let
C ----> the independent variable or input value
D ----> the dependent variable or output value
the value of k will be

For C=20, D=8 ---> 
For C=12.5, D=5 ---> 
the values of k are equal
therefore
There is a proportional relationship between the two quantities
The linear equation is equal to

Answer: f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.
Step-by-step explanation:
Given function: 
The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.
i.e. 
Hence, f(x) will have vertical asymptotes at x=-2 and x=2.
To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.
So, the graph will horizontal asymptote at 
i.e. 
Hence, f(x) will have horizontal asymptote at y=3.