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Radda [10]
3 years ago
7

Which type of front usually brings thunder clouds and storms

Chemistry
2 answers:
ladessa [460]3 years ago
6 0

Cold front forms Thunderclouds and storms.

Leni [432]3 years ago
3 0
A cold front brings thunder clouds and storms

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Which of the following is the smallest volume? 2500 ml, 30 cm^-3, 2.0x 10^-1L, 25mL
OLga [1]
The smallest volume is 30 cm^3.
8 0
3 years ago
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Electron electrical change is
Paha777 [63]

the electrons charge is negative

6 0
4 years ago
How many moles are there in 2.00 x 10^19 molecules of CCl4
HACTEHA [7]

Answer: 0.0000332mol

Explanation: 1mole of CCl4 contains 6.02x10^23 molecules.

Therefore, X mol of CCl4 will contain 2 x 10^19 molecules i.e

Xmol of CCl4 = 2 x 10^19/ 6.02x10^23 = 0.0000332mol

7 0
3 years ago
Materials Visible Uniform Not Visible Non- Uniform State of Matter 1. Sugar and water 2. Oil and water 3. Vinegar and water 4. S
salantis [7]

Answer:

1. Uniform, non visible

2. Visible, non uniform

3. Uniform, non visible

4. Visible, non uniform

5. Visible, non uniform

Explanation:

A heterogeneous mixture is simply any mixture that is not uniform in composition — it's a non-uniform mixture of smaller constituent parts. By contrast, a mixture that is uniform in composition is a homogenous mixture

visible state of matter is when you can easily difference two components of a mixture

non visible is when the state of the matter in the substance is not visible to the eye, it can't be differentiated

4 0
3 years ago
Read 2 more answers
Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi
bija089 [108]

<u>Answer:</u> The value of K_c for the net reaction is \frac{K_b}{K_w}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b

<u>Equation 2:</u>  H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}

The net equation follows:

B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=K_1\times K_2

We are given:  

K_1=K_b

K_2=\frac{1}{K_w}

Putting values in above equation, we get:

K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}

Hence, the value of K_c for the net reaction is \frac{K_b}{K_w}

7 0
3 years ago
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