4x^2(3x^2-8x+6)
(4*3)(x^(2+2))+(4*-8)(x^(2+1))+(4*6)(x^(2+0))
12x^4-32x^3+24x^2
Answer:
area: 454.2 sq.cm
perimeter: 77.7 cm
Step-by-step explanation:
to find area, find the area of all the separate shapes and add them together:
semi-circle:
radius is 12 cm
area =
= 226.2 sq.cm
separate the trapezoid into two right triangles and a rectangle.
area for triangles:
(5)(12) = 30
30 x 2 = 60 sq.cm (since there are two triangles)
area for rectangle:
12 x 14 = 168 sq.cm
area of whole shape: 226.2 + 60 + 168 = 454.2 sq.cm
for perimeter, just add the length of the exterior sides together.
we have some unknown sides, such as the semicircle and the sides of the trapezoid
we can find the hypotenuse of the triangles we used earlier to find the sides of the trapezoid with pythagorean theorem




c = 13 cm
to find the outside perimeter of the semi-circle, solve as if you were finding the circumference of a normal circle and divide it in half
= 37.7 cm
now add it all up:
14 + 13 + 13 +37.7 = 77.7
16.75% mark up.
To find this, minus the difference....
23,000 - 19,700 = 3,300..
then divide by the first cost...
23,000 ÷ 3,300 = 0.1675
now multiply that by 100...
0.1675 x 100 = 16.75%
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Answer:</u></h3>
Option: D
Horizontal stretching.
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Step-by-step explanation:</u></h3>
We have to find the effect on the graph of the function f(x)=2x when it is replaced by f(0.5 x).
We know that when a parent function f(x) is replaced by f(kx) then either the graph is stretched horizontally or shrinked horizontally.
if k>1 then the graph is shrinked horizontally.
if k<1 then the graph is stretched horizontally.
Hence here k=0.5<1 so the graph of the function is stretched horizontally.
5x2x9x9
10x81
810 is your answer