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densk [106]
1 year ago
6

Evelyn wants to enlarge a 5” x 7” photograph. She plans to enlarge it to fit a frame that is 16” x 20”. Will Evelyn’s photo reta

in the same proportions? Explain your reasoning.
Mathematics
1 answer:
nordsb [41]1 year ago
8 0

Evelyn’s photo will not retain the same proportions.

<h3>What is the Scale of enlargement?</h3>

When we talk of scale of enlargement, we are simply referring to a transformation where we dilate the object by a scale factor. What this means is that all dimensions of the new object must have the same scale with corresponding dimensions of initial object.

Now, when we enlarge a 5” x 7” photograph to fit into a frame of 16” x 20”, then both corresponding sides must have same ratio or scale of enlargement.

Let us check the scales of enlargement;

16"/5" = 3.2 as scale factor

20/7 = 2.857 as scale factor

Thus, we can conclude that Evelyn’s photo will not retain the same proportions.

Read more about Scale of Enlargement at; brainly.com/question/3457976

#SPJ1

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Ainat [17]

Answer:

The value of y in the given equation is B. 30.

Step-by-step explanation:

y = 2x² - 4x             x = 5

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y = 2(25) - 20         Square 5 and multiply 4 by 5

y = 50 - 20             Multiply 2 by 25

y = 30

Hope this helps,

❤<em>A.W.E.</em><u><em>S.W.A.N.</em></u>❤

6 0
3 years ago
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Molodets [167]

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Multiplying and dividing with integers. You also have to pay attention to the signs when you multiply and divide. There are two simple rules to remember: When you multiply a negative number by a positive number then the product is always negative.

Step-by-step explanation:

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horrorfan [7]

The equation of the regression line is : Ŷ = 0.8571+0.8878X

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Using technology :

Input the values of X and Y into their appropriate column and plot :

The regression equation obtained is :

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Where :

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The regression plot is attached below

Learn more : brainly.com/question/18405415?referrer=searchResults

7 0
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In a scale drawing of an apartment 1 centimet represents 2 3/4 feet. If the length of the kitchen is 4 1/2cm on the scale drawin
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2 years ago
How do I solve these problems?
lesya [120]

Domain:\\D:x > 0\\\\\ln x=5.6+\ln(7.5)\ \ \ \ |-\ln(7.5)\\\\\ln x-\ln7.5=5.6\ \ \ |Use\ \log x-\log y=\log\dfrac{x}{y}\\\\\ln\dfrac{x}{7.5}=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\\dfrac{x}{7.5}=e^{5.6}\ \ \ \ |\cdot7.5\\\\\boxed{x=7.5e^{5.6}}\in D

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2 years ago
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