Let the numbers are a and b; a - 5 = 2b, and -------------- (1)a2 + b2 = 250 ----------------(2) rewriting and squaring of (1) is given as; a2 = 4b2 + 20b + 25 -------- (3) substituting (3) into (2) (4b2 + 20b + 25) + b2 = 250, thus 5b2 + 20b - 225 = 0 by dividing both sides by 5 b2 + 4b - 45 = 0 solving the quadratic for b, we will get b = -9 or 5, substituting these for b in (1), we will get a asa = -13 or 15 However, if a and b must be positive integer, then a = 15 and b = 5 is the answer
Answer:
19
(17 + 21)/2 = 19
Thus, the number halfway between 17 and 21 is 19.
Step-by-step explanation:
sin is the opposite side over the hypotenuse so
sin C is 8/ 17 or B
Remember
and
so maybe we want to find a and b such that
24/2=12, so 12*2=24 so
24/3=8, so 8*3=24 so
so
I think those are in factored index form
