To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
Answer:
D
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°, that is
∠ 1 + ∠ 2 + ∠ 3 = 180°
Given ∠ 1 + ∠ 2 = 134°, then
134° + ∠ 3 = 180° ( subtract 134° from 180° )
∠ 3 = 46° → D
Answer:
Sorry im not sure on this one...
Step-by-step explanation:
The third option is correct
