The equation of a circle in standard form is
where (h, k) is the center of the circle, and r is the radius if the circle.
We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.
M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).
To find the radius, we find the length of the given diameter and divided by 2.
Answer:20% i know because i had a question like this
Answer:
60 °F
Step-by-step explanation:
The function can be put into vertex form:
T(x) = 0.264(x² -18x) +81 . . . . factor the leading coefficient from 1st 2 terms
Now, we add the square of half the x-coefficient inside parentheses and subtract the same quantity outside parentheses.
T(x) = 0.264(x² -18x +81) +81 -0.264·81
T(x) = 0.264(x -9)² +59.616
The low temperature for the day was approximately 59.6 °F, which rounds to 60 °F.
The pythagorean theorem states that a^2+b^2=c^2.
3^2 is 9.
9+9=18
The square root of 18 is approximately 4.24.
a.
b.
c.4.24
Y=15x+32, then plug in 3 for x, and you would get 77