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3 years ago

Its an humble request to the moderators please see to the attachment

Mathematics

1 answer:

Tamiku [17]3 years ago

6 0

Answer:

Okay im will ask them Thank You For Ur Response

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What is greater 1/3 or 3/5

8090 [49]

3/5 is greater the. 1/3

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3 years ago

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stiv31 [10]

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3 years ago

What is the equation of the line that passes through the point (5, 4) and has a slope<br> of<br> 6/5

Sati [7]

Answer:

y=6/5x-2

Step-by-step explanation:

y=mx+C

Y=6/5X+C

4=6+c

c=-2

y=6/5x-2

5 0

3 years ago

Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran

anastassius [24]

(x; y) -> (x - 2; y + 4)

J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)

K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)

L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)

M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)

5 0

3 years ago

The time between arrivals of customers at the drive-up window of a bank follows an exponential probability distribution with a m

castortr0y [4]

Answer:

a) 50.34% probability that the arrival time between customers will be 7 minutes or less.

b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 10 minutes:

This means that $m = 10, \mu = \frac{1}{10} = 0.1$

A. What is the probability that the arrival time between customers will be 7 minutes or less?

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

50.34% probability that the arrival time between customers will be 7 minutes or less.

B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3)$

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

$P(X \leq 3) = 1 - e^{-0.1*3} = 0.2592$

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3) = 0.5034 - 0.2592 = 0.2442$

24.42% probability that the arrival time between customers will be between 3 and 7 minutes

3 0

3 years ago