Question

5.

Answer 1

Answer:

B

Step-by-step explanation:

Given a quadratic equation in standard form, ax² + bx + c = 0 ( a ≠ 0 )

Then the sum of the roots = - $\frac{b}{a}$

A 2x² - 3x + 6 = 0

with a = 2 and b = - 3

sum of roots = - $\frac{-3}{2}$ = $\frac{3}{2}$ ≠ 3

B - x² + 3x - 3 = 0

with a = - 1 and b = 3

sum of roots = - $\frac{3}{-1}$ = 3 ← True

C $\sqrt{2}$ x² - $\frac{3}{\sqrt{2} }$ x + 1

with a = $\sqrt{2}$ and b = - $\frac{3}{\sqrt{2} }$

sum of roots = - $\frac{-\frac{3}{\sqrt{2} } }{\sqrt{2} }$ = $\frac{3}{2}$ ≠ 3

D 3x² - 3x + 3 = 0

with a = 3 and b = - 3

sum of roots = - $\frac{3}{-3}$ = 1 ≠ 3

Thus the equation with sum of roots as 3 is B