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LekaFEV [45]
3 years ago
10

5.

Mathematics
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Given a quadratic equation in standard form, ax² + bx + c = 0 ( a ≠ 0 )

Then the sum of the roots = - \frac{b}{a}

A 2x² - 3x + 6 = 0

with a = 2 and b = - 3

sum of roots = - \frac{-3}{2} = \frac{3}{2} ≠ 3

B - x² + 3x - 3 = 0

with a = - 1 and b = 3

sum of roots = - \frac{3}{-1} = 3 ← True

C \sqrt{2} x² - \frac{3}{\sqrt{2} } x + 1

with a = \sqrt{2} and b = - \frac{3}{\sqrt{2} }

sum of roots = - \frac{-\frac{3}{\sqrt{2} } }{\sqrt{2} } = \frac{3}{2} ≠ 3

D 3x² - 3x + 3 = 0

with a = 3 and b = - 3

sum of roots = - \frac{3}{-3} = 1 ≠ 3

Thus the equation with sum of roots as 3 is B

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