Answer:
Part a: So the number of business owners giving holiday gift to their employees from survey is 12.
Part b: p-value is 0.00003
Part c: value of p is less that a we reject the null hypothesis.
Step-by-step explanation:
Part a
number of business owners=20% x n
number of business owners= 0.2x 60
number of business owners=12
Part b
H0: p=0.46
H1: p<0.46
Here
n=60,
=0.2, p=0.46
So test statistics is given as
![z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}\\z=\frac{0.20-0.46}{\sqrt{\frac{0.46(1-0.46)}{60}}}\\z=\frac{-0.26}{0.064}\\z=-4.04](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%5C%5Cz%3D%5Cfrac%7B0.20-0.46%7D%7B%5Csqrt%7B%5Cfrac%7B0.46%281-0.46%29%7D%7B60%7D%7D%7D%5C%5Cz%3D%5Cfrac%7B-0.26%7D%7B0.064%7D%5C%5Cz%3D-4.04)
p-value is P(z<-4.04)= 0.00003
Part c
As value of p is less that a we reject the null hypothesis.