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3 years ago

If you get this I’ll mark you brilliance

Mathematics

1 answer:

djyliett [7]3 years ago

6 0

Answer:

$1256cm^{3}$

Step-by-step explanation:

Use the formula for the volume of a cylinder $V=3.14(r^{2}) h$ so then you plug in the values to get $1256cm^{3}$

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Which terms complete the factorization of x2+27x+162 represented by the model?

Anarel [89]

Answer:

9, 9x, 18x

Step-by-step explanation:

Hence the B. I hope this helps love!

4 0

2 years ago

Write the expression in complete factored form 4u^2(a-3)+q(a-3)

Sauron [17]

[ Answer ]

$\boxed{\bold{4au^{2} \ - \ 12u^{2} \ + \ aq \ - \ 3q}}$

[ Explanation ]

Factor: $4u^{2}$ (a - 3) + q(a - 3)

-------------------------------------

Expand $4u^2\left(a-3\right)$ : $4au^2-12u^2$

$4au^2-12u^2+q\left(a-3\right)$

Expand

$q\left(a-3\right)$ : $aq-3q$

Answer

$4au^2-12u^2+aq-3q$

$\boxed{\bold{[] \ Eclipsed \ []}}$

3 0

3 years ago

Solve for x 7x/2+5=8 o x=6/7 o x=26/7 o x=21/2 o x=91/2

pshichka [43]

Answer:

x = 6/7

Step-by-step explanation:

7x/2+5=8

Subtract 5 from each side

7x/2+5-5=8-5

7x/2 = 3

Multiply each side by 2/7

2/7 * 7/2x = 3*2/7

x = 6/7

7 0

2 years ago

Read 2 more answers

40 pts! PLEASE HELP FAST WILL MARK BRAINLIEST

muminat

Answer:

f(2) = 2.5×2-10.5

=5-10.5

=-5.5

g(2) = 64(0.5×2)

= 64×1

=64

f(3)=2.5×3-10.5

=7.5-10.5

=-3

g(3)=64(0.5×3)

=64×1.5

=96

f(4)=2.5×4-10.5

=10-10.5

=-500

g(4)=64(0.5×4)

=64×2

=128

f(5)=2.5×5-10.5

=12.5-10.5

g(5)=64(0.5×5)

=64×2.5

=150

I think it is the processs It will help you

7 0

2 years ago

baherus [9]

Answer: see proof below

Step-by-step explanation:

Given: cos 330 = $\frac{\sqrt3}{2}$

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

$\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}$

Proof LHS → RHS:

LHS cos 165

Double-Angle: cos (2 · 165) = 2 cos² 165 - 1

⇒ cos 330 = 2 cos² 165 - 1

⇒ 2 cos² 165 = cos 330 + 1

Given: $2 \cos^2 165 = \dfrac{\sqrt3}{2} + 1$

$\rightarrow 2 \cos^2 165 = \dfrac{\sqrt3}{2} + \dfrac{2}{2}$

Divide by 2: $\cos^2 165 = \dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \dfrac{2\sqrt3+4}{8}$

Square root: $\sqrt{\cos^2 165} = \sqrt{\dfrac{4+2\sqrt3}{8}}$

Scratchwork: $\cos^2 165 = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2$

$\rightarrow \cos 165 = \pm \dfrac{\sqrt3+1}{2\sqrt2}$

Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

$\rightarrow \cos 165 = - \dfrac{\sqrt3+1}{2\sqrt2}$

LHS = RHS $\checkmark$

4 0

3 years ago