Let
x---------> the length of the first piece
y---------> the length of the second piece
z---------> the length of the third piece
we know that
x+y+z=72 -------> equation 1
y=x+6 -----> solve for x
x=y-6 -------> equation 2
z=6+y -------> equation 3
substitute equation 2 and equation 3 in equation 1
[y-6]+y+[6+y]=72
3y=72
y=(72/3)=24 in
<u>Find the value of x</u>
x=y-6 -------> equation 2
x=24-6=18 in
<u>Find the value of z</u>
z=6+y -------> equation 3
z=6+24=30 in
therefore
<u>the answer is</u>
the length of the first piece is 18 in
the length of the second piece 24 in
the length of the third piece is 30 in
Answer:−3K−395,−374,−198,−187
Step-by-step explanation:
Remove parentheses.
1−3K−396,0−374,0−198,0−187
Simplify 1-3K-3961−3K−396 to -3K-395−3K−395.
−3K−395,0−374,0−198,0−187
Simplify 0-3740−374 to -374−374.
−3K−395,−374,0−198,0−187
Simplify 0-1980−198 to -198−198.
−3K−395,−374,−198,0−187
Simplify 0-1870−187 to -187−187.
−3K−395,−374,−198,−187
Answer:
5y+2=7
Step-by-step explanation:
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Answer:
trinomial
Step-by-step explanation:
