I am pretty sure it would be either .20 or .12.
There could be problems like there is a light which would flicker in every 7 seconds and there is another one which would flicker in every 8 seconds. So, how many times would they flicker until they would flicker at the same time?
X = 34
<span>2+8-x=-24
</span>Add 2 + 8: 10-x=-24
Subtract 10 from each side: -x = -34
Change the signs from each side: x = 34
Answer:
for circle in circle: 75π
circle in square: 64-16π
note that answers are in exact form, since I don't know how the answer should be written (exact or decimal etc.)
Step-by-step explanation:
for circle in circle, we see that smaller circle (white circle) has radius 5 and big circle has radius 10. therefore we can find area of shaded area by doing
area of big - area of small
10²π - 5²π = 100π - 25π = 75π
circle in square, applying the same method, we can do square-circle
since the circle is inscribed in the square, the circle's diameter is 8, so its radius is 4
8²-4²π = 64-16π
Answer:
Step-by-step explanation:
-9x + 6y = -30
-7x + 12y = -16
18x - 12y = 60
-7x + 12y = -16
11x = 44
x = 4
-36 + 6y = -30
6y = 6
y = 1
(4,1)