The range is how long the graph extends vertically. So, the lowest value is -9 (since the graph extends down until -9) and the highest value is 9 (since the graph extends up until 9). The lowest value goes in the first box and the highest value goes in the second box. The range is:
-9 ≤ <em>g</em>(<em>t </em>) ≤9
Answer:
I:23/48
ii 25/48
Step-by-step explanation:
30min=0.5hr
total time exercised: 11+0.5=11.5hr
Divided by total hours of a day:
11.5/24=115/240=23/48
ii:(48-23)/48
Answer:
0.322 × 10¹² /L
Step-by-step explanation:
Data provided in the question:
Number of cells counted with blue-stained granulofilamentous material
i.e number of RET = 100
The red blood cells count = 3.22 × 10¹² /L
Hematocrit = 30%
Now,
RET% = [ [ Number of RET ] ÷ 1000 RBCs ] × 100%
= [ 100 ÷ 1000 ] × 100%
= 0.1 × 100%
= 10%
also,
Absolute reticulocyte count = ( %RET × RBC count ) ÷ 100
= [ 10 × 3.22 × 10¹² /L ] ÷ 100
= 0.322 × 10¹² /L
Invert the divisor and then multiply 7/9 by your result:
7 -7 -49
--- * ------ = ---------
9 11 99
