(a) converges; consider the function <em>f(x)</em> = <em>a</em> ˣ, which converges to 0 as <em>x</em> gets large for |<em>a</em> | < 1. Then the limit is 2.
(b) converges; we have
4ⁿ / (1 + 9ⁿ) = (4ⁿ/9ⁿ) / (1/9ⁿ + 9ⁿ/9ⁿ) = (4/9)ⁿ × 1/(1/9ⁿ + 1)
As <em>n</em> gets large, the exponential terms vanish; both (4/9)ⁿ → 0 and 1/9ⁿ → 0, so the limit is 1.
(c) converges; we know ln(<em>n</em> ) → ∞ and arctan(<em>n</em> ) → <em>π</em>/2 as <em>n</em> → ∞. So the limit is <em>π</em>/2.
4a^2b and 6ab^3
first, find the greatest common factor of ur coefficients 4 and 6.....and that is gonna be 2
as for ur variables and exponents....take the lowest ones
so both have an " a " and a " b " variable....the lowest a term is just " a "...and the lowest " b " term is b
so the GCF of these 2 terms are : 2ab
The mathematical representation of Boyle's law is P1V1 = P2V2. The answer to your question is C. I hope that this is the answer that you were looking for and it has helped you.
Answer:
on my quzlet page last year it is 25
Step-by-step explanation:
Answer:
28.274
Step-by-step explanation:
