The diameter is the length from one point on the circle to another, passing through the center. The radius is the length from a point on the circle to its center, so we can always find the diameter by doubling the radius. In this case, with a radius of 7, our diameter is 7 · 2 = 14

5 0

3 years ago

Differentiate f(x) = \frac{x^{3}-4 x+1}{x^{3}}.

miv72 [106K]

$f(x) = \frac{x^{3}-4 x+1}{x^{3}}\\
f'(x)=\frac{(3x^2-4)\cdot x^3-(x^3-4x+1)\cdot3x^2}{x^6}\\
f'(x)=\frac{x^2(3x^3-4x-3x^3+12x-3)}{x^6}\\
f'(x)=\frac{8x-3}{x^4}\\
$

7 0

3 years ago

Please helpppppppppp

Anit [1.1K]

Answer:add 126 and 21 and 1.19

Step-by-step explanation:

126+21+1.19=

hope this helped

8 0

2 years ago

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