If x is length of the diagonal then
x^2 = 3^2 + 4^2 = 25
x = sqrt25 = 5
Diagonal is 5 units long
1) 1 degree = 1*10^-10 A= 6.9 * 10^-9 nm
Answer:
The three numbers are 56/5, -39/5 and 78/5.
Step-by-step explanation:
EQUATION 1:
First number: x
Second number: y
Third number: z
x + y + z = 19
EQUATION 2:
Sum of following is 77
Twice the first number: 2x
5 times the second number: 5y
6 times the third number: 6z
So, 2x + 5y + 6z = 77
EQUATION 3:
Difference between first and second number is 19.
x - y = 19
Equation 1: x + y + z = 19
Equation 2: 2x + 5y + 6z = 77
Equation 3: x - y = 19
1. Find x in terms of y
x - y = 19
x = 19 + y
2. Find y in terms of z by putting the value of x in first and second equation
x + y + z = 19
(19 + y)+ y + z = 19
2y + z = 19 - 19
2y + z = 0
y = -z/2
and
2(19+y)+5y+6z=77
now putting the value of y in this equation
2(19-z/2)+5(-z/2)+6z=77
38 - z -5z/2 +6z = 77
5z/2 + 38 = 77
5z/2 = 39
z = 78/5
Now, y = -z/2
y = (-78/5)/2
y = -39/5
and x = 19 + y
x = 19 - 39/5
x = 56/5
Therefore, the three numbers are 56/5, -39/5 and 78/5.
Keyword: Sum
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Answer:
(x + y - 2xy)*(x + y + 2xy)
Step-by-step explanation:
x^2-4x^2y^2+y^2+2*x*y
=x^2 + 2xy + y^2 - (2xy)^2
=(x + y)^2 - (2xy)^2
=(x + y - 2xy)*(x + y + 2xy)