All categories

3 years ago

I need help with part B please helpppppppp

Mathematics

1 answer:

KatRina [158]3 years ago

3 0

your answer for each would be the factor of whatever ur answer is for example 10 times 1.5 is ur first then so on and so forth

You might be interested in

Please help me with c this is confusing also is b correct?

OlgaM077 [116]

Answer: See attached.

Step-by-step explanation:

6 0

3 years ago

17.253 to the nearest tenth

Vlad1618 [11]

Answer:

17.3

Step-by-step explanation:

tens ones. tenths hundredths thousandths

1 7 . 2 5 3

We are rounding to the nearest tenth

We are rounding the 2 so we look at the 5. If it is 5 or above we round up.

Since it is, we will round the 2 to a 3

17.3

7 0

3 years ago

Read 2 more answers

If T(n)=3n-1,what is the 3rd term?

exis [7]

Plug in 3 for n, since you're looking for the third term.
T(1) = 3(1) - 1 = 2
T(2) = 3(2) - 1 = 5
T(3) = 3(3) - 1 = 8
It would be 8.

4 0

3 years ago

Sue and Cathi have $20 left for a cab fare home. The cab fare is $3 per mile plus a $2 fixed charge. What is the maximum number

larisa [96]

Answer:

6 miles

Step-by-step explanation:

20 - 2 is 18, 18/3 is 6.

7 0

3 years ago

A car, originally valued at 70,000 in 2006 depreciates exponentially at a rate of 4% each year. Round the expected value of the

lora16 [44]

Answer:

$42,890

Step-by-step explanation:

The standard form for an exponential equation is

$y=a(b)^x$

where a is the initial amount value and b is the growth rate or decay rate and t is the time in years. Since we are dealing with money amounts AND this is a decay problem, we can rewrite accordingly:

$A(t)=a(1-r)^t$

where A(t) is the amount after the depreciation occurs, r is the interest rate in decimal form, and t is the time in years. We know the initial amount (70,000) and the interest rate (.04), but we need to figure out what t is. If the car was bought in 2006 and we want its value in 2018, a total o 12 years has gone by. Therefore, our equation becomes:

$A(t)=70,000(1-.04)^{12}$ or, after some simplification:

$A(t)=70,000(.96)^{12}$

First rais .96 to the 12th power to get

A(t) = 70,000(.6127097573)

and then multiply.

A(t) = $42,890

8 0

4 years ago