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spin [16.1K]
3 years ago
8

6x + 4x - 1 = 2(5x + 4)

Mathematics
1 answer:
garik1379 [7]3 years ago
8 0

Answer: no solutions

Step-by-step explanation:

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X-3/-7 ≤ 8<br> Solve the inequality.
Veronika [31]

Answer:

x is less than or equal to 59/7

Step-by-step explanation:

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3 years ago
the hypotenuse of a right triangle is 3 cm and one of the legs is 1 cm what is the length of the other leg ?
Afina-wow [57]

Answer:

2\sqrt{2}

Step-by-step explanation:

let the other leg be x

Using Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 1² = 3²

x² + 1 = 9 ( subtract 1 from both sides )

x² = 8 ( take the square root of both sides )

x = \sqrt{8}

  = \sqrt{4(2)}

  = \sqrt{4} × \sqrt{2} = 2\sqrt{2} ← exact value

4 0
3 years ago
Math, please <br>I need to know how to simply
Aleks [24]

How to simplify : keep on dividing the numbers until you get to the lowest number.


EX: Simplify 36


What number goes into 36..... 9!


so 36/9

=4

3 0
4 years ago
Which of the following functions is graphed?
lora16 [44]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Gabriela coleciona moedas e em sua coleção há 165 moedas de ouro,220 moedas de prata e 275 moedas de bronze. Ela deseja organiza
kondor19780726 [428]

Answer: 55 coins in each box (12 boxes in total)

Step-by-step explanation:

The question in english is as follows:

Gabriela collects coins and in her collection there are 165 gold coins, 220 silver coins and 275 bronze coins. She wants to organize this collection in boxes that have the same number of coins and in such a way that each box contains the largest possible number of coins of a single type.

Under these conditions, how many coins Gabriela should put in each box?

So, we have 165 gold coins, 220 silver coins and 275 bronze coins, which sum in total 660 coins.

If we want to organize these coins in boxes with the same number of coins, we have to calculate the greatest common divisor among these three numbers:

<u>Divisors for 165:</u> 33, 5, 1

<u>Divisors for 220:</u> 44, 5, 1

<u>Divisors for 275:</u> 55, 5, 1

As we can see, the greatest common divisor is 55, this means we have to put 55 coins of the same type in each box.

In addition, taking into account we have a total of 660 coins; if we divide this by 55 we have as a result 12 boxes.

Therefore, Gabriela has to put 55 coins of the same type in 12 boxes.

7 0
3 years ago
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