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sertanlavr [38]
3 years ago
6

segment AB is dilated from the origin to create segment A prime B prime at A' (0, 6) and B' (6, 9). What scale factor was segmen

t AB dilated by? one half 2 3 4
Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

4

Step-by-step explanation:

I took the test and got it right.

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Solve for z. -2 (52 - 4) +62 = -4​
Masja [62]

Answer:

if you learned, PEMDAS then it be easier! soo I'll help.

Step-by-step explanation:

-2 ( 52- 4 ) is 48. 48 + 62= 110

if that's wrong, then I'm sorry!

1

62

48

——

110

6 0
3 years ago
Integration of (3X(X^2+3)^4) dx<br><img src="https://tex.z-dn.net/?f=%20" id="TexFormula1" title=" " alt=" " align="absmiddle" c
dimaraw [331]

Answer:


Step-by-step explanation:

\int 3x(x^2+3)^4 \ dx.

It is apparently obvious we could expand the bracket and integrate term-by-term. This method would work but is very time consuming (and you could easily make a mistake) so we use a different method: integration by substitution.

Integration by substitution involves swapping the variable x for another variable which depends on x: u(x). (We are going to choose u for this question).

The very first step is to choose a suitable substitution. That is, an equation u=f(x) which is going to make the integration easier. There is a trick for spotting this however: if an integral contains both a term and it's derivative then use the substitution u=\text{The Term}.

Your integral contains the term x^2 + 3. The derivative is 2x and (ignoring the constants) we see x is also in the integral and so the substitution u=x^2+3 will unravel this integral!

Step 2: We must now swap the variable of integration from x to u. That means interchanging all the x's in the integrand (the term being integrated) for u's and also swapping (dx" to "du").

u=x^2+3 \Rightarrow \frac{du}{dx}=2x \Rightarrow dx = \frac{1}{2x} du

Then,

\int 3x(x^2+3)^4 \ dx = \int 3x \cdot u^4 \cdot \frac{1}{2x} du = \int \frac{3}{2}u^4\ du.

The substitution has made this integral is easy to solve!

\int \frac{3}{2}u^4\ du= \frac{3}{10}u^5 + C

Finally we can substitute back to get the answer in terms of x:

\int 3x(x^2+3)^4 \ dx = \frac{3}{10}(x^2+3)^5+C

8 0
3 years ago
A rectangles width is 5 feet less than its length. Write a quadratic function that expresses the rectangles area in terms of its
Ira Lisetskai [31]

Answer:

Area = L²-5L

Step-by-step explanation:

Area = length * width

Length = L

Width = L - 5

Area = L * (L-5) = L²-5L

4 0
3 years ago
Giving brainlist to correct answer!
Oksana_A [137]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
9. Hue wants to buy two necklaces, one for
pishuonlain [190]

Answer:

$71.59

Step-by-step explanation:

43.25+26.25

=69.5

69.5*\frac{103}{100}

69.5*1.03

=71.585

8 0
3 years ago
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