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3 years ago

Cómo pueden ser las variables estadísticas?

1 answer:

6 0

Answer: Una variable es cualquier característica, número o cantidad que se puede medir o contar. Una variable también se puede llamar un elemento de datos. La edad, el sexo, los ingresos y gastos del negocio, el país de nacimiento, los gastos de capital, las calificaciones de clase, el color de los ojos y el tipo de vehículo son ejemplos de variables.

Step-by-step explanation:

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Do the set of points in the figure represent a function? 16.5 4 3 2 Yes No

Vladimir79 [104]

yes because none of the numbers are repeated bb ♡

3 0

4 years ago

-2(bx-5)=16 The value of x in terms of b is? That value of x when b is 3?

grin007 [14]

Answer:

Step-by-step explanation:

Let's solve for b.

−2(bx−5)=16

Step 1: Add -10 to both sides.

−2bx+10+−10=16+−10

−2bx=6

Step 2: Divide both sides by -2x.

−2bx/−2x=6/−2x

b=−3x

Answer:

b=−3x

———————————————————

Let's solve for x.

−2(bx−5)=16

Step 1: Add -10 to both sides.

−2bx+10+−10=16+−10

−2bx=6

Step 2: Divide both sides by -2b.

−2bx/−2b=6/−2b

x=−3b

Answer:

x=−3b

Hope this helps you out

7 0

4 years ago

Gloria worked for 6 hours a day for 2 days at the bank and earned $114.24. How much did she earn per hour?

marysya [2.9K]

$9.52 is the answer

4 0

3 years ago

Read 2 more answers

What is 3 times the sum of a and b? This needs to be written as an algebraic expression!

igomit [66]

(b+a)3 hope this helps

5 0

3 years ago

Consider the following sample set of scores. Assume these scores are from a discrete distribution. 21 29 32 38 38 45 50 64 72 10

ASHA 777 [7]

Answer:

Original data: 21 29 32 38 38 45 50 64 72 100

$\bar X = \frac{21+29+32+38+38+45+50+64+72+100}{10}=48.9$

Mode =38.

$Median = \frac{38+45}{2}=41.5$

Change 1: 2 29 32 38 38 45 50 64 72 100

$\bar X = \frac{2+29+32+38+38+45+50+64+72+100}{10}=47$

Mode =38.

$Median = \frac{38+45}{2}=41.5$

Change 2: 29 32 38 38 45 50 64 72 100

$\bar X = \frac{29+32+38+38+45+50+64+72+100}{9}=52$

Mode =38.

$Median = 45$

Step-by-step explanation:

Original data: 21 29 32 38 38 45 50 64 72 100

The mean is calculated with the following formula:

$\bar X = \frac{\sum_{i=1}^{10} X_i}{10}$

And if we replace we got:

$\bar X = \frac{21+29+32+38+38+45+50+64+72+100}{10}=48.9$

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have an even number of points the median is calculated as the average between the observations 5 and 6 from the dataset ordered.

$Median = \frac{38+45}{2}=41.5$

Change 1: 2 29 32 38 38 45 50 64 72 100

The mean is calculated with the following formula:

$\bar X = \frac{\sum_{i=1}^{10} X_i}{10}$

And if we replace we got:

$\bar X = \frac{2+29+32+38+38+45+50+64+72+100}{10}=47$

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have an even number of points the median is calculated as the average between the observations 5 and 6 from the dataset ordered.

$Median = \frac{38+45}{2}=41.5$

Change 2: 29 32 38 38 45 50 64 72 100

Now the sample size is 9 instead of 10

The mean is calculated with the following formula:

$\bar X = \frac{\sum_{i=1}^{9} X_i}{9}$

And if we replace we got:

$\bar X = \frac{29+32+38+38+45+50+64+72+100}{9}=52$

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have odd number of points the median is calculated from the 5 position of the dataset ordered.

$Median = 45$

7 0

4 years ago