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3 years ago

Pls help meeeee I need to pass

Mathematics

2 answers:

Westkost [7]3 years ago

5 0

Answer:

f(14)=1\2x-2

=1/2(14) - 2

=14/2 -2

= by BODMAS( Bracket, of, division, multiplication, addition, subtraction)

= 7-2

vodomira [7]3 years ago

5 0

Answer:

F(14) = 5

Step-by-step explanation:

In attachment

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7. Five swimmers entered a competition. Four of the swimmers had their turns. Their scores are 9.8, 9.75, 9.79 and 9.81 seconds

arsen [322]

Answer:

We must order these decimals from least to greatest. Then we must determine how the least compares with the winning score.

9.80 -> 3

9.75 -> 1

9.79 -> 2

9.81 -> 4

The least decimal is 9.75. Now we must determine how 9.75 compare with the winning score.

The last swimmer must get a score less than 9.75 seconds in order to win.

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2 years ago

What is the next term of the arithmetic sequence?<br> -3, -7, -11, -15,

Dmitriy789 [7]

Answer:

-19

Step-by-step explanation:

Take the second term and subtract the first term to find what we are adding (or subtacting ) each time

-7 -(-3) =

-7+3

-4

We are subtracting 4 each time

Subtract 4 from the next term

-15 -4 = -19

The next term is -19

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4 years ago

What is the LCM of 13/16a^3b^3, 11/30a^5b

vichka [17]

Answer:

The L.C.M of given numbers is $\frac{143}{240}a^5b^3$ .

Step-by-step explanation:

The given expressions are

$\frac{13}{16}a^3b^3$

$\frac{11}{30}a^5b$

The factors of given expressions are

$\frac{13}{16}a^3b^3=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b$

$\frac{11}{30}a^5b=\frac{11}{15}\times \frac{1}{2}\times a\times a\times a\times a\times a\times b$

$L.C.M.=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b\times \frac{11}{15}\times a\times a$

$L.C.M.=\frac{143}{240}\times a^5\times b^3$

$L.C.M.=\frac{143}{240}a^5b^3$

Therefore, the L.C.M of given numbers is $\frac{143}{240}a^5b^3$ .

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3 years ago

two coins and one six sided number cube are tossed together. What is the probability of getting two heads and a four?

Elis [28]

Answer:

The probability of getting two heads and a four is 1/24

Step-by-step explanation:

The probability of getting a head upon a single toss of a coin, assuming the coin is fair is 1/2.

The probability of getting two heads upon tossing two coins together will simply be the product of the individual probabilities;

P (HH) = 1/2 * 1/2 = 1/4

On the other hand, the probability of getting a four upon rolling a six sided number cube is;

1/6

This is because the number 4 occurs only once in a total possible of 6 numbers.

Therefore, the probability of getting two heads and a four;

P (HH4) = 1/2 * 1/2 * 1/6 = 1/24 since the three events are independent.

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3 years ago

Which of the following are true about dilation

Blizzard [7]

Answer:

All of them are true except D.

Step-by-step explanation:

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3 years ago