1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arturiano [62]
3 years ago
10

Which expression equivalent to 8 +n

Mathematics
2 answers:
CaHeK987 [17]3 years ago
7 0

Answer:

9n

Step-by-step explanation:

shepuryov [24]3 years ago
4 0

Answer:

add 8 and 9 17

Step-by-step explanation:

You might be interested in
NEED ASAP hurry plz<br><br>Write a story that would explain the graph below.
pishuonlain [190]

Answer:

A kid leaping happily to home after school

8 0
2 years ago
The vertex of the parabola below is at the point (1,3), and the point (2,6) is
Inessa05 [86]

Answer:

B. y=3(x-1)2 + 3

Step-by-step explanation:

Given that

vertex of the parabola is at the point (1,3)

let's verify, if the option B is the correct equation of the parabola.

y=3(x-1)^2 + 3\\ \\y=3(x^2+1-2x) + 3\\\\y=3x^2+3-6x + 3\\\\y=3x^2-6x + 6....Eq1

comparing to standard equationof parabola (standard quadratic equation), we get

a=3, b=-6 and c=6

to find the vertex we use formula for x- coordinate as x=-b/2a

x=-(-6)/2(3)\\\\x=6/6\\x=1

to find y put x=1 in the Eq1, we get

y=3(1)^2-6(1)+6\\\\y=3-6+6\\\\y=3

vertex =(x,y) = (1, 3)

thus vertex of the parabola from the equation y=3(x-1)2 + 3 is (1,3), thus verified

7 0
2 years ago
There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?
anygoal [31]

Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

  • Where A is the initial amount, in this case, 7800g.
  • k is a constant that depends on the half-life.
  • t is the time in days.

Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

e^{k*8} = 1/2

ln(e^{k*8}) = ln(1/2)

k*8 = ln(1/2)

k = ln(1/2)/8 = -0.0866

Then the function is:

A(t) =  7800g*e^{-0.0866*t}

So now we just need to evaluate this in t = 40.

A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

3 0
2 years ago
What is the answer to this
Softa [21]

Answer:

5 f

Re-order terms so that constants are on the left

. 5

5 f

solution

5 f

7 0
3 years ago
jenette ordered a large bucket of popcorn at the movies.the graph shows the amount of popcorn in her bucket over time
Elenna [48]

Answer:

A

Step-by-step explanation:

5 0
2 years ago
Other questions:
  • Help me with this math problem please
    10·2 answers
  • What z score in a normal distribution has 33% of all score above it? ap stats quiz 2.2a answers?
    8·1 answer
  • An aquarium holds 11.25 cubic feet of water, and 2.5 feet long and 1.5 feet wide. What is its depth?
    5·1 answer
  • W = f d, solve for d
    13·1 answer
  • What is 5.0706 rounded to the nearest hundredth
    9·1 answer
  • HELP ME WITH THE EXERCISES PLEAASE
    7·1 answer
  • Creating box plots<br> Problem<br> Which data set could be represented by the box plot shown below?
    10·1 answer
  • Pls HELPPPP!!!!!!!!!!
    10·2 answers
  • What's the slope of<br> (4,5) &amp; (-1,-5)<br> helppppp
    12·2 answers
  • Simplify the expression.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!