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3 years ago

Simplify the expression below 13y+x-7y

Mathematics

2 answers:

soldier1979 [14.2K]3 years ago

7 0

Answer: 5y + x

Step-by-step explanation: As you first step to this problem, change all your minus signs to plus negatives.

To simplify, we can only combine what are called our like terms and in this problem, we have one y-term and we have a pair of like terms in our x-terms.

So let's start by combining our y-terms.

13y + -7y simplifies to 5y.

Now we have one x-term so we have 5y + x.

BaLLatris [955]3 years ago

7 0

<h3><u>Answer:</u></h3>

=x+6y

<h3><u>Let's simplify step-by-step.</u></h3>

13y+x−7y

=13y+x+−7y

<h3><u>Combine Like Terms:</u></h3>

=13y+x+−7y

=(x)+(13y+−7y)

=x+6y

<h3><u>Answer:</u></h3>

=x+6y

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3 years ago

Write a quadratic equation given the roots -1/3 and 5, show your work

Travka [436]

$\boxed{(x - a)(x - b) = 0}$

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

$x = - \frac{1}{3} \\ x = 5$

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

$(x + \frac{1}{3} )(x - 5) = 0$

Here we can convert the expression x+1/3 to this.

$x + \frac{1}{3} = 0 \\ 3x + 1 = 0$

Rewrite the equation.

$(3x + 1)(x - 5) = 0$

Simplify by multiplying both expressions.

$3 {x}^{2} - 15x + x - 5 = 0 \\ 3 {x}^{2} - 14x - 5 = 0$

<u>Answer</u><u> </u><u>Check</u>

Substitute the given roots in the equation.

$3 {(5)}^{2} - 14(5) - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0$

$3( - \frac{1}{3} )^{2} - 14( - \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) + \frac{14}{3} - 5 = 0 \\ \frac{1}{3} + \frac{14}{3} - \frac{15}{3} = 0 \\ \frac{15}{3} - \frac{15}{3} = 0 \\ 0 = 0$