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Dimas [21]
3 years ago
9

A scientist from the United States conducts an experiment using miles per hour to measure speed why might this be confusing for

scientists and other countries
Mathematics
1 answer:
juin [17]3 years ago
4 0
The scientific mathematical language barrier.
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Justin walked 3 miles north and 6 miles west. starting from the same point, tina walked 2 miles south and 4 miles east. how far
Darya [45]
Basically, Justin and Tina's paths form two right-angled triangles whose hypotenuses(?) form a straight line between their end points. Therefore we need to find the two distances from the starting point and add them.
Justin walked 3 miles north and 6 miles west so his distance from the start is the square root of 9+36 or 45. This can be simplified to 3√5. 
Tina walked 2 miles south and 4 miles east so her distance from the starting point is the square root of 4 + 16 or 20. This can be written as 2√5.
If we add these two distances together we get 5√5. Hence, Justin and Tina are 5√5 miles away from each other.
6 0
3 years ago
The combined area of two squares is 80 square centimeters. Each side of one square is twice as long as a side of the other squar
o-na [289]

The length of each side of the larger square is 8 cm.

<u>Step-by-step explanation</u>:

Step 1 ;

  • The combined area of two squares = 80 sq.cm
  • The side of small square = x
  • The side of larger square = 2x

Step 2 :

Area of the square = a^2

Area of small square + area of large square = 80

x^2 + (2x)^2 = 80

x^2 + 4x^2 = 80

5x^2 = 80

x^2 = 80/5

x^2 = 16

x = ±4

Step 3 :

Since length cannot be negative, the value of x= 4

∴ The length of the side of small square = 4cm

The length of the side of larger square = 2x = 8cm

5 0
3 years ago
Please help asap i will mark branlist
Serjik [45]

Answer:

C) Total Interest and Principal

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
The rule for the number of fish in a home aquarium is 1 gallon of water for each inch of fish length. Marta's aquarium holds 22
Anuta_ua [19.1K]

Answer:

Fish A is 4 inches.

Fish B is 5 inches.

Step-by-step explanation:

22=3a+2b

and

32=3a+4b

So,

a=4 and b=5

7 0
3 years ago
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