If you have at least as many equations as your have unknown variables, the 'system' is solvable (unless the equations are copies of eachother).
In this case, isolate one letter and plug it in the other. I'm going for the 2a in the bottom one (it doesn't matter)
2a - 4b = 12 => (divide by two and move the b's to the other side)
a = 6 + 2b. (plug this one into the top equation)
4(6+2b) + 6b = 10 => 24+8b+6b = 10 => 24 + 14b = 10 => 14b = -14 => b=-1
a = 6 + -2 = 4.
So a=4 and b=-1.
Answer:
16,00
Step-by-step explanation:
9 years is the (time)
divide the 27 years by 9 to see how many times it doubles
the ans is 3
now simply divide the value which is $4,800 by the 3
this gives you 1,600
Y + 2 = x, or y + 12 = 2x
Given:
An equation in a coincidental system of two linear equations:
2x + 3y = -27
The other equation is
_y = _x - 102
Rearrange the second equation to be identical to the first
_y - _x = -102
Determine the factor, -102/-27 = 3.78
for x, 2 * 3.78 = 7.56
for y, 3 * 3.78 = 11.33
The second equation, 11.33y - 7.56x = -102
48 oz?
Step-by-step explanation:
I don't know if you are just asking or what not but I belive it is 48 ozs but I could be wrong
