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IgorLugansk [536]
2 years ago
7

Create 5 expressions that are equivalent to the expression 12 x to the power of 4

Mathematics
1 answer:
Lerok [7]2 years ago
5 0

Answer:

4x*3x^3

2x^2*6x^2

12x*x^3

x^2*12x^2

Step-by-step explanation:

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Answer: $595

is the correct answer

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Mark deposits $12,000 into an account that pays 4% interest, compounded annually, for 5 years. Saul deposits $10,000 into an acc
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Solving Rational Inequalities and use sign diagram to sketch the graph. Image attached for better understanding.
hjlf

Answer:

x ∈ (-∞ , -2) ∪ (1, 3)

Step-by-step explanation:

The expression is already factored. Note that for the polynomial that appears in the numerator (x-3)(x + 2) there are 2 roots:

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For the polynomial that appears in the denominator there is 1 root:

x = 1

Note that x = 1 does not belong to the domain of f(x) because it zeroes the denominator of the function and the division between zero is not defined.

With these three roots we do the study of signs to find out when f(x)

Observe the attached image

Note that:

(x-3) when x

(x + 2) when x

(x-1) when x

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5 0
3 years ago
Find the value of x.
bonufazy [111]

Answer:

61

Step-by-step explanation:

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On a standardized test with a normal distribution the mean score was 67.2. The standard deviation was 4.6. What percent of the d
Reika [66]

Answer:

P ( -1 < Z < 1 ) = 68%

Step-by-step explanation:

Given:-

- The given parameters for standardized test scores that follows normal distribution have mean (u) and standard deviation (s.d) :

                         u = 67.2

                         s.d = 4.6

- The random variable (X) that denotes standardized test scores following normal distribution:

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Find:-

What percent of the data fell between 62.6 and 71.8?

Solution:-

- We will first compute the Z-value for the given points 62.6 and 71.8:

                          P ( 62.6 < X < 71.8 )

                          P ( (62.6 - 67.2) / 4.6 < Z < (71.8 - 67.2) / 4.6 )

                          P ( -1 < Z < 1 )

- Using the The Empirical Rule or 68-95-99.7%. We need to find the percent of data that lies within 1 standard about mean value:

                          P ( -1 < Z < 1 ) = 68%

                          P ( -2 < Z < 2 ) = 95%

                          P ( -3 < Z < 3 ) = 99.7%

6 0
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