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velikii [3]
3 years ago
13

Answer please !!! i need help asap

Mathematics
2 answers:
maksim [4K]3 years ago
5 0

Answer:

A. Undefined will be your answer

Step-by-step explanation:

Dovator [93]3 years ago
3 0
Your answer should be A.
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Help me please I am completely lost
Irina-Kira [14]
Okay, your answer is 182. You really do not need to look at the crazy stuff on the paper about the crazy numbers. Look at the graph. It is counting up by 20's on the left side. But on the right side, the whole time it is counting up by 13's. Your answer is 182.
6 0
3 years ago
Read 2 more answers
How many terms of the arithmetic sequence {1,22,43,64,85,…} will give a sum of 2332? Show all steps including the formulas used
MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the <em>n</em>-th term of the sequence, <em>a</em> (<em>n</em>), is given recursively by

• <em>a</em> (1) = 1

• <em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 21 … … … for <em>n</em> > 1

We can find the explicit rule for the sequence by iterative substitution:

<em>a</em> (2) = <em>a</em> (1) + 21

<em>a</em> (3) = <em>a</em> (2) + 21 = (<em>a</em> (1) + 21) + 21 = <em>a</em> (1) + 2×21

<em>a</em> (4) = <em>a</em> (3) + 21 = (<em>a</em> (1) + 2×21) + 21 = <em>a</em> (1) + 3×21

and so on, with the general pattern

<em>a</em> (<em>n</em>) = <em>a</em> (1) + 21 (<em>n</em> - 1) = 21<em>n</em> - 20

Now, we're told that the sum of some number <em>N</em> of terms in this sequence is 2332. In other words, the <em>N</em>-th partial sum of the sequence is

<em>a</em> (1) + <em>a</em> (2) + <em>a</em> (3) + … + <em>a</em> (<em>N</em> - 1) + <em>a</em> (<em>N</em>) = 2332

or more compactly,

\displaystyle\sum_{n=1}^N a(n) = 2332

It's important to note that <em>N</em> must be some positive integer.

Replace <em>a</em> (<em>n</em>) by the explicit rule:

\displaystyle\sum_{n=1}^N (21n-20) = 2332

Expand the sum on the left as

\displaystyle 21 \sum_{n=1}^N n-20\sum_{n=1}^N1 = 2332

and recall the formulas,

\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n

\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2

So the sum of the first <em>N</em> terms of <em>a</em> (<em>n</em>) is such that

21 × <em>N</em> (<em>N</em> + 1)/2 - 20<em>N</em> = 2332

Solve for <em>N</em> :

21 (<em>N</em> ² + <em>N</em>) - 40<em>N</em> = 4664

21 <em>N</em> ² - 19 <em>N</em> - 4664 = 0

Now for the problem I mentioned at the start: this polynomial has no rational roots, and instead

<em>N</em> = (19 ± √392,137)/42 ≈ -14.45 or 15.36

so there is no positive integer <em>N</em> for which the first <em>N</em> terms of the sum add up to 2332.

4 0
2 years ago
Help me please thank you
BabaBlast [244]

Let's use a formula in order to find how much the interior angles are supposed to add up to.

(n-2)×180; n is the number of angles.

(5-2)×180= 3×180=540

We need for the interior angles to add up to 540. Let's make an equation.

100+102+108+121+x=540

431+x=540; let's find x.

540-431= 109

So, X= 109°

3 0
3 years ago
What is the answer to -3+y=-5
Stolb23 [73]

Answer:

y=-2

Step-by-step explanation:

you are solving for the variable y

add 3 to the opposite side, so it cancels out

y=-5+3

y=-2

4 0
3 years ago
Read 2 more answers
Am I right or wrong (don't answer the last one!)
S_A_V [24]

Answer:

1) Distributive Property of Multiplication (The terms are distributed)

2) Addition property of equality (Adding 14 to both sides)

3) Simplifying (We simplified the expression)

4) Division property of equality (Dividing both sides by 6)

6 0
3 years ago
Read 2 more answers
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