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1 year ago

The volume of the cube is given as V= x³, where x is the side length of the cube. Find the domain of the volume of

Mathematics

1 answer:

katovenus [111]1 year ago

7 0

Answer: None of the choices

Step-by-step explanation:

1. It couldn't be integers (whole numbers positive or negative), because a cube couldn't have a negative volume.

2. It could be natural numbers, but the problem is, that a volume could have decimal values, for example, 3.62 meters cubed which a natural number doesn't support.

3. Set of whole numbers is the same as integers, so it can't be that.

4. None of the choices, which in my opinion is the correct one.

I'm not sure it is correct, but I hope I helped you!

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levacccp [35]

I think it is b but no positive

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2 years ago

Select the ratio equivalent to tan (o)

CaHeK987 [17]

Answer:

tangent = opp over adj

Step-by-step explanation:

6 0

2 years ago

(x³ + ³) / (x - y)<br> Do not include parentheses in your answer.

Lubov Fominskaja [6]

The simplified expression of $\frac{x^3 + (-y)^3}{(x - y}$ is $x^2+xy+y^2$

<h3>Complete question</h3>

Simplify the expression: (x³ + (-y)³) / (x - y)

Do not include parentheses in your answer.

<h3>How to simplify the expression?</h3>

The expression is given as:

$\frac{x^3 + (-y)^3}{(x - y}$

Open the inner bracket

$\frac{x^3 -y^3}{(x - y}$

Apply the difference of two cubes to the numerator

$\frac{(x-y)(x^2+xy+y^2)}{(x - y}$

Cancel out the common factors

$x^2+xy+y^2$

Hence, the simplified expression of $\frac{x^3 + (-y)^3}{(x - y}$ is $x^2+xy+y^2$

Read more about expressions at:

brainly.com/question/723406

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4 0

1 year ago

ANSWER ONLY THANK YOU

viktelen [127]

A. (1,4)

EXPALINATION :

IF WE WRITE THE VALUE x = -1 AND y = 4

THEN, y= -8x - 4

4= -8×-1-4

4= 8-4

AND SECOND EQUATION IS : y = x+5

y = -1 +5

y = 4

hence, solved and explained

thank you And mark me brainlist if you understand And hopes so

8 0

1 year ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 81% of the students were found to be

Dvinal [7]

Answer:

The probability that a student is proficient in mathematics, but not in reading is, 0.10.

The probability that a student is proficient in reading, but not in mathematics is, 0.17

Step-by-step explanation:

Let's define the events:

L: The student is proficient in reading

M: The student is proficient in math

The probabilities are given by:

$P (L) = 0.81\\P (M) = 0.74\\P (L\bigcap M) = 0.64$

$P (M\bigcap L^c) = P (M) - P (M\bigcap L) = 0.74 - 0.64 = 0.1\\P (M^c\bigcap L) = P (L) - P (M\bigcap L) = 0.81 - 0.64 = 0.17$

The probability that a student is proficient in mathematics, but not in reading is, 0.10.

The probability that a student is proficient in reading, but not in mathematics is, 0.17

5 0

3 years ago