Here you go!! Those are the points and labeled for you
so.. whatever "x" and "y" amounts are, we know that, added together, they must yield 14lbs
thus x + y = 14
and whatever the cost of each is, 7x + 4y must be 14*5
7x+4y = 70
thus
solve for "x", to see how much of the $7/lb type will be needed
what about the $4/lb one? well, y = 14 - x
9514 1404 393
Answer:
- 22.0
- 15.0
- 30.0°
- 137.0°
Step-by-step explanation:
These are all Law of Cosine problems. A generic expression for the length of side 'c' opposite angle C, which is defined by sides 'a' and 'b' is ...
c² = a² +b² -2ab·cos(C)
The square root of this gives the side length:
c = √(a² +b² -2ab·cos(C))
Rearranging the equation, we can obtain an expression for the angle C.
C = arccos((a² +b² -c²)/(2ab))
These two formulas are used to solve the offered problems.
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1) AC = √(13² +14² -2·13·14·cos(109°)) ≈ √483.506
AC ≈ 22.0
__
2) BC = √(7² +10² -2·7·10·cos(123°)) ≈ √225.249
BC ≈ 15.0
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3) ∠B = arccos((24² +28² -14²)/(2·24·28)) = arccos(1164/1344)
∠B ≈ 30.0°
__
4) ∠B = arccos((6² +9² -14²)/(2·6·9)) = arccos(-79/108)
∠B ≈ 137.0°
Answer:
7/25
Step-by-step explanation:
