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Reptile [31]
3 years ago
11

Voris made 80 cookies this week. She baked 4 less than three times the total she made last week. Which equation, when solved for

Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0

the answer is c your very welcome

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Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.
natulia [17]

\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k

Divergence is easier to compute:

\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}

\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}

Curl is a bit more tedious. Denote by D_t the differential operator, namely the derivative with respect to the variable t. Then

\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}

\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k

\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k

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3 years ago
Find the least common denominator for these two rational expressions. 3/2n -2/5n
Zielflug [23.3K]
Every rational expression can be written in infinitely many equvialent  forms which is 3/3n-15/2.
8 0
3 years ago
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3x -2y = -6 and y = x+5
sweet [91]

Answer:

x = 4, y = 9.

Step-by-step explanation:

3x -2y = -6 and y = x+5

Substitute y = x + 5 in the first equation:

3x - 2(x + 5) = -6

3x - 2x - 10 = -6

x = -6 + 10

x = 4

So y = 4 + 5 = 9.

5 0
3 years ago
A sphere with a diameter of 8 inches. What is the surface area of the sphere shown? 16Pi in2 32Pi in2 64Pi in2 256Pi in2
Viefleur [7K]

Answer:

201.06 in^2/32Pi in2

Step-by-step explanation:

4Pi in2*8=32Pi in2

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3 years ago
What’s the slope between -14,-10 and 12,18
maria [59]

\bf (\stackrel{x_1}{-14}~,~\stackrel{y_1}{-10})\qquad (\stackrel{x_2}{12}~,~\stackrel{y_2}{18}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{18-(-10)}{12-(-14)}\implies \cfrac{18+10}{12+14}\implies \cfrac{28}{26}\implies \cfrac{14}{13}

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3 years ago
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