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iVinArrow [24]
3 years ago
15

On the first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75. The school took in $6

7 on the second day by selling 8 senior citizen tickets and 5 child tickets. What is the price each of one senior citizen tickets and one child tickets?
Mathematics
1 answer:
denis-greek [22]3 years ago
4 0

<u>ANSWER:</u>

The price of senior citizen ticket is $4 and price of child ticket is $7.

<u>SOLUTION: </u>

Given, first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75.  

The school took in $67 on the second day by selling 8 senior citizen tickets and 5 child tickets.  

We need to find what is the price each of one senior citizen tickets and one child tickets.

Let, the price of senior citizen ticket be "x" and price of child ticket be "y"

Then according to the given information,

3x + 9y = 75

x + 3y = 25  [by cancelling the common term 3.

x = 25 – 3y ---- (1)

And, 8x + 5y = 67 ---- (2)

Substitute (1) in (2)

8(25 – 3y) + 5y = 67

200 – 24y + 5y = 67

5y – 24y = 67 – 200

-19y = -133

y = \frac{133}{19}

y = 7

Now substitute y value in (1)

x = 25 – 3(7)

x = 25 – 21  = 4

Hence, the price of senior citizen ticket is $4 and price of child ticket is $7.

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algol [13]

Find the critical points of f(x,y):

\dfrac{\partial f}{\partial x}=-2x=0\implies x=0

\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12

All three points lie within D, and f takes on values of

\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}

Now check for extrema on the boundary of D. Convert to polar coordinates:

f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t

Find the critical points of g(t):

\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0

\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2

\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi

where n is any integer. There are some redundant critical points, so we'll just consider 0\le t< 2\pi, which gives

t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3

which gives values of

\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}

So altogether, f(x,y) has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0
3 years ago
Help finding angles 4, 3 ,2 ,5... Picture attached this time
Korvikt [17]

Angle 3 = 180° - 70°

Angle 3 = 110°

Angle 2 = 180° - (110° + 36°)

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Angle 5 = 180° - (110° + 62°)

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Angle 5 = 8°

I hope this helps.
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