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3 years ago

Solve the inequality for y. y-5<-14

Mathematics

2 answers:

matrenka [14]3 years ago

7 0

Y=-9 is the answer have a good day :)

dedylja [7]3 years ago

5 0

The answer is y=-9
negative 9 remember that

Move the constant to the right-hand side and change its sign and calculate

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A highway engineer specifies that a certain section of roadway covering a horizontal distance of 2km should have a downgrade of

Zigmanuir [339]

Answer:

$0.16km$

Step-by-step explanation:

A highway engineer wants to compute the change in elevation of a section of road. The horizontal distance of this section of road is 2km and downgrade is 8%

The slope formula is given by

$m=\frac{rise}{run}=\frac{x}{y}$

m = 8% = 8/100

run = y = 2km

$m =\frac{x}{y}$

$\frac{8}{100} =\frac{x}{2}$

$\frac{2*8}{100} =x$

$x=\frac{16}{100} =0.16km$

Verification:

$m=\frac{0.16}{2}= 0.08=8%$ %

3 0

3 years ago

Read 2 more answers

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Katarina [22]

Step-by-step explanation:

You can imagine this figure as a rectangle and cube

If you want volume of this irregular figure than you have to do it like this:

V(figure)= V(rectangle)+ V(cube)

V(figure)= a*b*c+ a³

V(figure)= 4*3*(I don't see dimension on the left)+ 3³

V(figure)=12*(I don't see dimension on the left)+ 27

And only you have to to do is to set this dimension which I can't see.

6 0

2 years ago

PLEASEEEE HELP ITS URGENT!!!!

Marrrta [24]

Answer:

f(x)=1/2x-6

Step-by-step explanation:

7 0

3 years ago

.764 as a percent .

Nookie1986 [14]

.764 in percentage form is 76.4%

3 0

3 years ago

Read 2 more answers

In a sample of 53 walking canes, the average length was found to be 34.3in. with a variance of 1.9. Give a point estimate for th

Anna11 [10]

Answer:

1.38

Step-by-step explanation:

The point estimate for the population standard deviation of the length of the walking canes is given as the squareroot of variance. Since variance is provided as 1.9 then the standard deviation will be

$\sqrt 1.9=1.37840487520902\approx 1.38$

Therefore, rounded off to two decimal places, the standard deviation is approximately 1.38

6 0

3 years ago