Solve the equation for exact solutions over the interval [0, 2π]. cos2x=−12
1 answer:
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First we need to write the factors of the polynomial. In order for 1, 4, and -3 to be roots, they need to be the x values that make the polynomial equal 0.
(x - 1) = 0
That would be the factor for x = 1 because when we plug 1 in for x we get 1 - 1 which equals 0.
Multiply all the factors together.
(x-1)(x-4)(x+3)=0
Now FOIL.
(x - 1) = 0
That would be the factor for x = 1 because when we plug 1 in for x we get 1 - 1 which equals 0.
Multiply all the factors together.
(x-1)(x-4)(x+3)=0
Now FOIL.
Solve what is in parenthesis first (5-9) = -4
Solve exponents next -4^3 = -64
Divide next
= -32
Lastly, subtract and resolve the negatives which become a positive number 125 - (-32) = 125 + 32 = 157
Solve exponents next -4^3 = -64
Divide next
= -32
Lastly, subtract and resolve the negatives which become a positive number 125 - (-32) = 125 + 32 = 157