It's mitochondrial
sorry if im wrong
hope it helps
Answer:
If the question is how many ATP molecules must be input to initiate the process of glycolysis than the answer would be 2. This would result in the total net gain of 2, because while four ATP molecules are produce it requires two to begin the whole process.
Answer:
In nature, populations are usually evolving. The grass in an open meadow, the wolves in a forest, and even the bacteria in a person's body are all natural populations. And all of these populations are likely to be evolving for at least some of their genes. Evolution is happening right here, right now!
To be clear, that doesn't mean these populations are marching towards some final state of perfection. All evolution means is that a population is changing in its genetic makeup over generations. And the changes may be subtle—for instance, in a wolf population, there might be a shift in the frequency of a gene variant for black rather than gray fur. Sometimes, this type of change is due to natural selection. Other times, it comes from migration of new organisms into the population, or from random events—the evolutionary "luck of the draw."
I hope this helps a little bit.
Sedimentary rocks<span> can be categorized into three groups based on sediment type. Most sedimentary rocks are formed by the </span>lithification<span> of </span>weathered<span> rock debris that has been physically transported and deposited. During the transport process, the particles that make up these rocks often become rounded due to abrasion or can become highly sorted. Examples of this type of sedimentary rock include </span>conglomerate<span> and </span>sandstone<span>. Scientists sometimes call this general group of sedimentary rocks </span>clastic<span>. The remaining types of sedimentary rocks are created either from chemical precipitation and crystallization, or by the lithification of once living </span>organic matter<span>. We identify these sedimentary rocks as being </span><span>non-clastic
So the Answer Would Be C</span>
