80,+84, +82, +79, +72, +97, +89, +97, +88, +79, +86, +90, +87 =
klemol [59]
Answer:
1110
Step-by-step explanation:
Coz I solved it
<h3>2
Answers: Choice C and choice D</h3>
y = csc(x) and y = sec(x)
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Explanation:
The term "zeroes" in this case is the same as "roots" and "x intercepts". Any root is of the form (k, 0), where k is some real number. A root always occurs when y = 0.
Use GeoGebra, Desmos, or any graphing tool you prefer. If you graphed y = cos(x), you'll see that the curve crosses the x axis infinitely many times. Therefore, it has infinitely many roots. We can cross choice A off the list.
The same applies to...
- y = cot(x)
- y = sin(x)
- y = tan(x)
So we can rule out choices B, E and F.
Only choice C and D have graphs that do not have any x intercepts at all.
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If you're curious why csc doesn't have any roots, consider the fact that
csc(x) = 1/sin(x)
and ask yourself "when is that fraction equal to zero?". The answer is "never" because the numerator is always 1, and the denominator cannot be zero. If the denominator were zero, then we'd have a division by zero error. So that's why csc(x) can't ever be zero. The same applies to sec(x) as well.
sec(x) = 1/cos(x)
Answer:
Step-by-step explanation:
<u>This is going to be an arithmetic progression:</u>
- 48500, 48500 + 1200, 48500 + 1200*2, ...
<u>So the first term is </u>
<u>and the common difference is </u>
<u>Sum of AP is:</u>
- S = (a₁ + aₙ)*n/2 = (2a₁ + (n - 1)d)*n/2
<u>Substitute and solve for n:</u>
- (2*48500 + (n - 1)*1200)*n/2 = 321000
- (97000 + 1200n - 1200)n = 642000
- 1200n² + 95800n - 642000 = 0
- 6n² + 479n - 3210 = 0
<u>Solving we get a positive root of:</u>
- n ≈ 6.21 and it rounds up to 7 years
Well, company (A) has a deposit of $10
Company (B) has one of $20
By definitions of the (co)tangent and cosecant function,
Turn everything into fractions with common denominators:
Recall that 
, so we can simplify both sides a bit.
On the left:
On the right:
(as long as 
, which happens in the interval 
when 
or 
)
So we have
