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zepelin [54]
3 years ago
10

Tell me both like what should i say in the sentence please ​

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0
1 is yes and 2 is no epa
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7x-5y=-15 and -14x+7y=0 Solve by elimination
geniusboy [140]

Answer: (5,10)

Step-by-step explanation:

multiply first equation with 2 and add it to second to eliminate X

7x-5y=-15  //*2

14x-10y=-30

-14x+7y=0

----------------

-3y=-30

y=-30/-3

y=10

7x=50-15

7x=35

x=35/7

x=5

4 0
3 years ago
Can someone please help me with this question ASAP.It is due tommorrow.
ololo11 [35]
D. All irrational numbers are rational numbers.

I attached the diagram my teacher showed us when we learned about this. I think it makes it a lot less confusing.

Hope this helps :)

7 0
2 years ago
Read 2 more answers
What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
2 years ago
Four students were asked to write an expression which has terms that have a greatest common factor of 8c. The expressions provid
wel

Answer:

Wyatt wrote the correct expression

Step-by-step explanation:

Here we are to evaluate which of the students wrote an expression with the highest common factor being 8c

For Tanya; 32c + 16c; 16c( 2 + 1); This is wrong as the highest common factor is 16c

For Wyatt, we have 8c - 48cd; factorizing, we have 8c(1-6cd); This is correct

For Xavier we have 36c-24c; 8 is not a factor of 36, so it won’t work

For Yang 8c + 40; 8(c+ 5); what we are trying to look for is 8c and not 8 so this is wrong also

3 0
3 years ago
Read 2 more answers
How do you do percent
Veronika [31]
Take the decimal and multiply it by 100.
7 0
3 years ago
Read 2 more answers
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