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Zigmanuir [339]

3 years ago

5

Mike is putting a ladder up against his mothers house to clean the roof. His mothers house is 24 feet tall and he is placing the

base of his ladder 7 feet away from the bottom of the house. How long is the ladder he is using

1 answer:

levacccp [35]3 years ago

3 0

The length of the ladder is 25 feet.

<u>Explanation:</u>

Height of the House, h = 24 feet

Distance between the house and the ladder, b = 7 feet

length of the ladder, x = ?

The house makes 90° with the base of the ladder.

Using pythagoras theorm,

x² = h² + b²

x² = (24)² + (7)²

x = √625

x = 25

Therefore, the length of the ladder is 25 feet.

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umka2103 [35]

3 cards

1/4 = x/12 1/4 = 3/12
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2 years ago

I need help with this V-4=v+2+7v-42 ??

zubka84 [21]

Answer:

$\boxed{\bold{v \ = \ \frac{36}{7}}}$

Step-by-step explanation:

Subtract v from both sides

$\bold{v-4-v=v+2+7v-42-v}$

Simplify

$\bold{-4=2+7v-42}$

Switch sides

$\bold{2+7v-42=-4}$

Group like terms

$\bold{7v+2-42=-4}$

Subtract the numbers: 2 - 42 = -40

$\bold{7v-40=-4}$

Add 40 to both sides

$\bold{7v-40+40=-4+40}$

Simplify

$\bold{7v=36}$

Divide both sides by 7

$\bold{\frac{7v}{7}=\frac{36}{7}}$

Simplify

➤ $\bold{v=\frac{36}{7}}$

5 0

3 years ago

Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the

s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

$F(x)=\sqrt{x-2}$

$G(x)=(x-2)^2$

$H(x)=x^2+2$

We compose F(x) and G(x) to get:

$(F\circ G)(x)=F(G(x))$

$(F\circ G)(x)=F((x-2)^2)$

$(F\circ G)(x)=\sqrt{(x-2)^2-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+4-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+2}$

$(F\circ G)(x)\ne x$

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

$(F\circ H)(x)=F(H(x))$

$(F\circ H)(x)=F(x^2+2)$

$(F\circ H)(x)=\sqrt{x^2+2-2}$

We simplify to get:

$(F\circ H)(x)=\sqrt{x^2}$

$(F\circ H)(x)=x$

Since $(F\circ H)(x)=x$ , H(x) is an inverse of F(x)

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3 years ago