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REY [17]
3 years ago
12

Given V=1/3(3.14)r^2h solve for r

Mathematics
1 answer:
Gnoma [55]3 years ago
5 0

The answer is r = √ v/1.046667h   (v over 1.046667h)

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When numbers are combined into a sum, we are doing ___.
JulijaS [17]
Addition 
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7 0
3 years ago
HELLO. I NEED HELP ON A HANDFUL OF QUESTIONS. PLEASE HELP. ​
galben [10]

Question 7: $3945

78,900÷100×5= 3,945

or 789,00×0.05= $3,945

Question 8: I think it may be $675.46 ( but I'm not sure)

$1010 is her annual insurance premium so to find one month we need to divide $1010 by 12

$1010÷12= $84.20

also her annual real estate tax is $938 and to find one month we need to divide this by 12 as well.

$938÷12=$78.20

and in order to find out her combined monthly payment we need to add them all together

$513.12+$84.16+$78.16= $675.46

Question 9: is False

Question 10: I don't know

Hope this helps

5 0
3 years ago
How do you do this question?
Alex Ar [27]

Step-by-step explanation:

(a) dP/dt = kP (1 − P/L)

L is the carrying capacity (20 billion = 20,000 million).

Since P₀ is small compared to L, we can approximate the initial rate as:

(dP/dt)₀ ≈ kP₀

Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.

20 = k (6,100)

k = 1/305

dP/dt = 1/305 P (1 − (P/20,000))

(b) P(t) = 20,000 / (1 + Ce^(-t/305))

6,100 = 20,000 / (1 + C)

C = 2.279

P(t) = 20,000 / (1 + 2.279e^(-t/305))

P(10) = 20,000 / (1 + 2.279e^(-10/305))

P(10) = 6240 million

P(10) = 6.24 billion

This is less than the actual population of 6.9 billion.

(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))

P(100) = 7570 million = 7.57 billion

P(600) = 20,000 / (1 + 2.279e^(-600/305))

P(600) = 15170 million = 15.17 billion

7 0
2 years ago
PLEASE HELP!!!!! WILL GIVE 5 STARS!! BRAINLIEST ANSWER!!!! 25 POINTS!!!!!
OLga [1]
0.7m=117-750.7m=42/0m=42/0m=60 miles they will be costing the same
7 0
3 years ago
Which equation is true for the function h(x) = 16*?
LekaFEV [45]

Answer:

opiton b

Step-by-step explanation:

To find out which equation satisfies h(x) we need to check with each option

We plug in x  value

A) h(–1.25) = –0.5

Plug in -1.25 for x  in h(x) = 16^x

That is not true

B) h(–0.5) = 0.25

Plug in -0.5 for x  

That is true.

C)  h(0.75) = 12

Plug in 0.75 for x  

That is not true.

D)  h(1.25) = 20

Plug in 1.25 for x  

That is not true

4 0
3 years ago
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