Answer:
The frequency of recessive allele should be 0.30.
Explanation:
According to Hardy-Weinberg equilibrium, sum of both dominant allele frequency (p) and recessive allele frequency (q) should be equal to 1 (p+q = 1).
Brown hair = dominant (p)
white hair = recessive (q)
49% mice are brown hair
so dominant genotype frequency = 0.49
According to Hardy-Weinberg principle, square root of the genotype (homozygous) is equal to allele frequency.
√p =√0.49 = 0.70
The dominant allele frequency is 0.7
Now, by this value we can find the recessive allele frequency by
p + q = 1
1 - 0.7 = 0.3
So, the recessive allele (white hair mice) frequency is 0.30.
The taxonomic category between kingdom and class is Phylum.
<span>Nephrotic syndrome is a kidney disorder characterized by excretion of too much protein in the urine. It is usually caused by damage to the glomeruli in the kidneys. In nephrotic syndrome, the glomeruli are affected by an inflammation that allows proteins such as albumin, antithrombin or the immunoglobulins to pass through the cell membrane and appear in urine (usually they don’t appear). Nephrotic syndrome causes swelling (edema), usually in feet and ankles, and increases the risk of other health problems.</span>
They all fulfill the 8 characteristics of all living things to be classified as a living organism. Those 8 characteristics are being able to evolve as a group, reproduce, respond to stimuli, made up of cells, fulfill the universal genetic code, obtain and use energy, maintain homeostasis, and grow and develop.
