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damaskus [11]
3 years ago
8

-nr+70<50 show answer for N4b-2d=25 show answer for D

Mathematics
1 answer:
horsena [70]3 years ago
7 0

Answer:

-nr+70 <50

or,-nr+70-50 <50-50

or,20-nr <0

or,20-nr-20<-20

or,-nr<-20

or,nr/n<20/n

or,r <20/n

same as

4b-2d=25

or,4b=25+2d

or(4b-25)/2=d

Step-by-step explanation:

we must try to solve equation for answer

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How do you slove 2/3 (9x -6) = 14
Ivanshal [37]

Answer:

x=3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2

3

(9x−6)=14

(

2

3

)(9x)+(

2

3

)(−6)=14(Distribute)

6x+−4=14

6x−4=14

Step 2: Add 4 to both sides.

6x−4+4=14+4

6x=18

Step 3: Divide both sides by 6.

6x

6

=

18

6

x = 3

5 0
2 years ago
Find each measurement. Assume that each figure is not drawn to scale.
ivanzaharov [21]

Answer:

1) 2 1/4 inches (2.25)

2) 5.3 millimeters

3) X=10 and YZ=60

Step-by-step explanation:

Number 1, you just add the measurements because n and q is the start and end of the line segment.

Number 2, you are given the whole measurement, and you know FG which is 9.7, so you subtract the 15 (whole measurement) by 9.7, which is 5.3.

Number 3, you know that XY and YZ equal XZ, so 8x+1 would equal 81. Do the math, you would get 8x=80 and then x=8. Now you know x, plug it in for 6x, so 6(10)=60.

4 0
2 years ago
Write a polynomial equation of least degree with roots 2, -1 and 4.
Rasek [7]
A polynomial with roots a and b is (x - a)(x - b).

(x - 2)(x - (-1))(x - 4) = 0

(x - 2)(x + 1)(x - 4) = 0

has roots 2, -1, and 4.
3 0
2 years ago
Suppose you have a water-balloon launcher. The balloon is 3 ft high when it leaves the launcher. Use the equation 0 = ?16t2 + 38
mario62 [17]

Answer:

t = 2.5 s

Step-by-step explanation:

Suppose you have a water-balloon launcher. The balloon is 3 ft high when it leaves the launcher. Its equation is :

16t^2 + 38.8t + 3 =0

The above equation is a quadratic equation. The general equation is :

ax^2+bx+c=0

Here, a = 16, b = 38.8 and c = 3

The solution of quadratic equation is given by :

x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}\\\\t=\dfrac{-38.8\pm \sqrt{(38.8)^2-4\times (-16)\times 3} }{2\times (-16)}\\\\t=\dfrac{-38.8+\sqrt{(38.8)^{2}-4\times-16\times3}}{-2\times16}, \dfrac{-38.8-\sqrt{(38.8)^{2}-4\times-16\times3}}{-2\times16}\\\\t=-0.075\ s,2.5\ s

So, at t = 2.5 s the balloon is in air.

8 0
2 years ago
Plz solve this question and pls show your work
STALIN [3.7K]

z = 10


14 = 64 - 5z


Subtract

-50 = -5z


Divide

10 = z

8 0
3 years ago
Read 2 more answers
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